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27t^2-26t-1=0
a = 27; b = -26; c = -1;
Δ = b2-4ac
Δ = -262-4·27·(-1)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-28}{2*27}=\frac{-2}{54} =-1/27 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+28}{2*27}=\frac{54}{54} =1 $
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